8t(t-1)-6(t^2-1)=2t(t-4)

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Solution for 8t(t-1)-6(t^2-1)=2t(t-4) equation: 



8t(t-1)-6(t^2-1)=2t(t-4)

We move all terms to the left:

8t(t-1)-6(t^2-1)-(2t(t-4))=0

We multiply parentheses

8t^2-6t^2-8t-(2t(t-4))+6=0



We calculate terms in parentheses: -(2t(t-4)), so:

2t(t-4)

We multiply parentheses

2t^2-8t

Back to the equation:

-(2t^2-8t)



We add all the numbers together, and all the variables

2t^2-8t-(2t^2-8t)+6=0

We get rid of parentheses

2t^2-2t^2-8t+8t+6=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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